Get index of repeated elements in list python

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WebDec 10, 2024 · You can use enumerate and check the next index in the list. If an element is not equal to the element in the next index, it is the last duplicate: lst = [1, 1, 1, 2, 2, 3, 3, 4, 5] result = [i for i, x in enumerate (lst) if i == len (lst) - 1 or x != lst [i + 1]] print (result) # [2, 4, 6, 7, 8] Share Improve this answer Follow WebHow to count the number of repeated items in a list in Python - Python programming example code - Python programming tutorial - Actionable Python programming code. …

Repeat Elements of a List in Python - PythonForBeginners.com

WebHow to count the number of repeated items in a list in Python - Python programming example code - Python programming tutorial - Actionable Python programming code. Data Hacks. Menu. Home; R Programming; ... Accessing Last Element Index of pandas DataFrame in Python (4 Examples) bricktown elks lodge

python - Finding the index of an item in a list - Stack Overflow

WebApr 25, 2015 · You can use the count () method from the list object to get a count equal to 1: >>> A= [1, 2, 3, 2, 5, 1] >>> unique= [i for i in A if A.count (i)==1] >>> unique [3, 5] Alternatively the Counter () class from the collections module can be used: A = [1, 2, 3, 2, 5, 1] c = Counter (A) print [key for key, count in c.iteritems () if count==1] Share WebJul 31, 2011 · last_occurence=len(yourlist)-yourlist[::-1].index(element)-1 just easy as that.no need to import or create a function. Share. Improve this answer. Follow answered Apr 13, 2024 at 10:09. Prabu M ... Find last index of element in list with duplicate elements python. 0. index() of last occurrence in list in python. 0. WebAnd some of the indexes have duplicate values in the 9th column (the type of DNA repetitive element in this location), and I want to know what are the different types of repetitive elements for individual locations (each index = a genome location). I'm guessing this will require some kind of groupby and hopefully some groupby ninja can help me out. bricktown events mount union pa

python - Using .index() with a list that has repeated elements

Python: count repeated elements in the list - Stack Overflow

WebDec 17, 2024 · Python is a great language for doing data analysis, primarily because of the fantastic ecosystem of data-centric python packages. Pandas is one of those packages and makes importing and analyzing data much easier.. Pandas Index.get_duplicates() function extract duplicated index elements. This function returns a sorted list of index elements … WebAug 17, 2024 · Example 3: Working of the index () With two Parameters only. In this example, we will see when we pass two arguments in the index function, the first argument is treated as the element to be searched and the second argument is the index from where the searching begins. list_name.index (element, start) Python3. list1 = [6, 8, 5, 6, 1, 2] bricktown events 2021WebJan 18, 2014 · As per the str.index docs, signature looks like this. str.index(sub[, start[, end]]) The second parameter is the starting index to search from. So you can pass the index which you got for the first item + 1, to get the next index. bricktown haunted house

"WebNov 1, 2011 · It turns out that, if the input array doesn't have duplicate elements, all methods are more or less equally fast, independently of whether the input data is a Python list or a NumPy array. If the input array is large, but contains just one unique element, then the set, dict and np.unique methods are costant-time if the input data is a list. " - Get index of repeated elements in list python

Get index of repeated elements in list python

python - Get all indexes for duplicate elements in a list - Stack Overflow

WebDec 16, 2024 · There are much more efficient ways of finding duplicates in list in python (yours is O(n^2)), and its probably just better using numpy library to do it: import numpy … WebWith most optimize way with respect to time and space complexity: Step-1: Start travelling the original array from last, Step-2: Once you find the given element. Step-3: Return the index = l - i -1; where l = total length of the array, i = index of the element in step-2. – ArunDhwaj IIITH. Sep 4, 2024 at 17:37.

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WebMar 23, 2012 · Then it goes to the next element 31, with index 1, and checks if element 31 is present in the input_list[2:] (i.e., from index 2 till end of list), Because 31 is present in input_list[2:], it will return 31. similarly it goes through all the elements in the list, and will return only the repeated/duplicate elements into a list. WebJan 3, 2016 · Use enumerate to keep track of the index and a set to keep track of element seen: l = [1, 1, 2, 3] inds = [] seen = set () for i, ele in enumerate (l): if ele not in seen: inds.append (i) seen.add (ele) If you want both: inds = [] seen = set () for i, ele in enumerate (l): if ele not in seen: inds.append ( (i,ele)) seen.add (ele)

WebJun 9, 2011 · You can use a list comprehension with enumerate: indices = [i for i, x in enumerate (my_list) if x == "whatever"] The iterator enumerate (my_list) yields pairs (index, item) for each item in the list. Using i, x as loop variable target unpacks these pairs into the index i and the list item x. WebJul 11, 2024 · Teams. Q&A for work. Connect and share knowledge within a single location that is structured and easy to search. Learn more about Teams

WebJul 26, 2024 · You can simply use function enumerate (lst) it returns elements index_number and value. for example lst [0] = 1 the case above index_number is 0 and value is 1 so you can just use enumerate function for returning index number using if condition (returns it when the value is 3) WebAug 26, 2024 · While working with Python list, sometimes, we require to check for duplicates and may also sometimes require to track their indices. This kind of …

WebNov 14, 2024 · Using generator expressions and comprehensions this is pretty straightforward. First let's get all values that appear more than once in a set. x = [1.2, 2.4, 3.1, 4.0, 5.6, 6.5, 1.2, 3.1, 8.1, 23.6, 29.3] multiples = set (a for a in set (x) if x.count (a) > 1) Now, to get the indexes, we can use enumerate and a list comprehension to only ...

WebApr 8, 2024 · Find indexes of consecutive items in lists. and return a 2d list with the indexes of the repeating values: new_list = [] i = 0 while i < len (x)-1: if x [i] == x [i+1]: new_list.append ( [x [i],x [i+1]] i += 1. x is not necessarily sorted but has at least one series of repeating values. For example x can also be: bricktown gospel fellowshipWebFeb 8, 2024 · To repeat the elements in a list in python, we insert the existing elements of a list to the same list. In this way, the elements in a list get repeated. For instance, If we … bricktown event centerWebAug 22, 2024 · How do I get the index of a duplicated string in a list? Traversing through the length of the list so that we can keep a track of each index and print the index. … bricktown events centerWebIndex: "Return the index in the list of the first item whose value is x." a simple solution would be: for i in range (len (top)): if top [i] == 3: print ('recommendation found at: ' + str (i)) Share Improve this answer Follow answered Apr 9, 2016 at 17:03 Maximilian Peters 29.6k 12 83 96 Add a comment Not the answer you're looking for? bricktowne signature villageWebFind an index of duplicate elements in list Python Example Simple example code. a = [1, 2, 3, 2, 1, 5, 6, 5, 5, 5] res = [idx for idx, item in enumerate (a) if item in a [:idx]] print (res) Output: Another example using collections You have … bricktown filmsWebOct 7, 2008 · @stefanct this likely does double the complexity, I believe the in operator on a list has linear runtime. @ApproachingDarknessFish stated it would iterate twice which answers your question, and is right in saying that doubling the linear complexity is … bricktown entertainment oklahoma cityWebApr 23, 2014 · Using a dictionary to count the items in a list (8 answers) Closed 6 months ago. I am new to Python. I am trying to find a simple way of getting a count of the number of elements repeated in a list e.g. MyList = ["a", "b", "a", "c", "c", "a", "c"] Output: a: 3 b: 1 c: 3 python python-2.7 Share Follow edited Feb 24, 2024 at 8:01 galoget 712 9 15 bricktown fort smith